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10+13.9x+0.4x^2=0
a = 0.4; b = 13.9; c = +10;
Δ = b2-4ac
Δ = 13.92-4·0.4·10
Δ = 177.21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13.9)-\sqrt{177.21}}{2*0.4}=\frac{-13.9-\sqrt{177.21}}{0.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13.9)+\sqrt{177.21}}{2*0.4}=\frac{-13.9+\sqrt{177.21}}{0.8} $
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